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Multiply $(-2)_{10}$ and (-5)_{10}$ using Booths algorithm.
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[Note: Refer Q1 for the theory and flowchart of Booth’s algorithm]

Using the flowchart, we can solve the given question as follows:

$(-5)_{10}$ = 1011(in 2’s complement)

$(-2)_{10}$ =1110(in 2’s complement)

Multiplicand (B) = 1011

Multiplier (Q) =1110

And initially $Q{-1} = 0$

Count =4

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This is the required and correct result.

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