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Multiply (−2)10 and (-5)_{10}$ using Booths algorithm.
1 Answer
written 8.7 years ago by |
[Note: Refer Q1 for the theory and flowchart of Booth’s algorithm]
Using the flowchart, we can solve the given question as follows:
(−5)10 = 1011(in 2’s complement)
(−2)10 =1110(in 2’s complement)
Multiplicand (B) = 1011
Multiplier (Q) =1110
And initially Q−1=0
Count =4
This is the required and …