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Multiply $(-2)_{10}$ and (-5)_{10}$ using Booths algorithm.
1 Answer
written 8.5 years ago by |
[Note: Refer Q1 for the theory and flowchart of Booth’s algorithm]
Using the flowchart, we can solve the given question as follows:
$(-5)_{10}$ = 1011(in 2’s complement)
$(-2)_{10}$ =1110(in 2’s complement)
Multiplicand (B) = 1011
Multiplier (Q) =1110
And initially $Q{-1} = 0$
Count =4
This is the required and correct result.