
Consider above diagram in which BX & AY are velocity vectors
AB is diameter of circle & C is ICR of disk.
Now, triangles XBI & IAY are similar
Therefore, BI/IA=BX/AY=3/1.5=2BI=2IA______(i)Also,BI+IA=BA(diameter )=0.48____(ii)
From (i) & (ii),
BI=0.32m & IA=0.16m
Now, as BI=0.32 & BC=0.24,
IC(distance between centre of circle & ICR) =0.08
Now, w of disc is VB/IB=3/0.32=9.375rad/sVc=w∗IC=9.375∗0.08=0.75m/s
Now, for calculation of VD , we need ID
Applying cosine rule,
ID=√[(0.24)2+(0.08)2−2∗(0.24)(0.08)cos135]=0.315m
Now, VD=w∗ID=9.375∗0.315=2.953m/s
Velocity of C is 0.75m/s & velocity of D is 2.953m/s
