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Due to slipping, points A & B on the rim of disk have the velocities as shown in fig. Determine the velocities of the centre point C & point D on rim at this instant.

Take radius of disk 0.24m

enter image description here

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enter image description here

Consider above diagram in which BX & AY are velocity vectors

AB is diameter of circle & C is ICR of disk.

Now, triangles XBI & IAY are similar

Therefore, $BI/IA = BX/AY = 3/1.5 =2 \\ BI = 2 IA\text {______}(i) \\ Also, BI + IA = BA(\text {diameter …

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