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The car starts from rest and moves in a straight line such that for a short time its velocity is defined by v=(9t2+2t)m/s. Where t is in seconds.

Determine its position and acceleration when t = 3 sec.

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v=9t2+2t(i) For displacement at t=3s, dxdt=9t2+2t x=30(9t2+2t)dt  [Assuming initial position at x=0] =[3t3+t2]30 x=90mAns For acceleration at t=3s Differentiate (i) w.r.t ‘t’ a=(18t+2)t=3 a=56m/s2Ans

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