Mumbai university > FE > SEM 1 > Applied Physics 1

Marks: 3M

Year: Dec 2012

Given:-

Mobility of Holes, $μ = 0.025m^2 / V$

Hall Co-efficient, $R_H = 2.25 × 10^{-5} m^3/C$

To Find: Resistivity(ρ )

Solution:

We know that,

$ρ = \frac{R_H}{μ} = \frac{2.25 × 10^{-5}}{0.025}$

$ρ = 10^{-3} Ω_{-m}$