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Find the necessary force to raise a heavy stone block of 2000 N. Take coeff. of friction as 0.25 for all surfaces. Neglect the weight of wedge. Wedge angle is 15.

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Applying conditions of equilibrium to the stone

Fx=N2+N1cos75+µN1cos15=0_______(i)FY=2000µN2+N1sin75µN1sin15=0 _____(ii)

Solving 2 equations, we get

N1=2576.83N    N2=1289.19N

Now, Applying conditions of equilibrium to the wedge

Fx=N1cos75µN1cos15+PµN=0_______(i)FY=NN1sin75+µN1sin15=0_____(ii)

Solving eqns (i) & (ii)

N=2322.293N & P=1869.76N

The necessary force is P=1869.76N

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