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A pole is held in a place by 3 cables. If the force of each cable acting on pole is as shown in fig. Determine the resultant.
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written 8.4 years ago by
teamques10
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This is concurrent system of force system of 3 forces at O
Let F1 be the force in cable OA
$F1 = F1. rOA \\ = 600[(-18i - 16j - 24k)/(\sqrt{182+162+242})] \\ = -317.6i - 282.4j - 423.5k N $
Let F2 be the force in cable OB
$F2 = F2 . rOB \\ = 400[(15i - 20j - 24k)/(\sqrt{152+202+242})] \\ = -173.1i - 230.8j - 277k N $
Let F3 be the force in cable OC
$F3 = F3 . rOC \\ = 800[(4i + 6j - 24k)/(\sqrt{42+62+242})] \\ = 127.7i + 191.5j - 766.2k N $
Now, resultant force
$R = F1 + F2 +F3 \\ R = -16.8 i - 321.7 j - 1466.7 k N $
The resultant of force system is $R = -16.8 i - 321.7 j - 1466.7 k N $
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