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Force Γ=80i+50j−60k passes through a point A (6, 2, 6). Compute its moment about a point B(8,1,4).
1 Answer
written 8.7 years ago by |
Given :- →F=80i+50j−60k→rA=6i+2j+6k→rB=8i+j+4k
To find:-
Moment about B→(MB)
Solution:-
Position vector of A w.r.t B is
$\vec{r_{AB} }= \vec{r_A } - \vec{r_B }\\ =(6i+2j+6k)-(8i+j+4k) \\ \vec{r_{AB}} = -2i+j+2k \\ Now, \\ …