The tensions act away from the point. Hence the tensions will be acting away from point B. Let tensions in AB and AC be A and C respectively.

Let the angles opposite to A, B and C be $α,β$ and $γ$ respectively $$\text {From planar geometry we can see that } α = 130; β = 110; γ= 120$$

Applying Lami’s theorem,

$A/sinα = B/sinβ = C/sinγ $

Using first part,

$A/ \sin130 = (30 \times 9.8) / \sin 110 \\ A= 240N$

Similarly,

$(30 \times 9.8)/ \sin110 = C/ \sin120 \\ C= 271N$