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Two identical rollers each of weight 500 N and radius r are kept on a right angle frame ABC having negligible weight.

Assuming smooth surfaces, find the reactions induced at all contact surfaces.

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Since there are many unknowns, we can not solve the sum by using one F.B.D. Since the system is in equilibrium, we can break it as shown below:-

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Applying static conditions of equilibrium,

$∴ ΣM_C \cong 0 ( +ve) \\ ∴ R_3 × r+500 \cos30 ×r+500 \sin30 ×r+ R_5×r=0 \\ ∴ R_3×r=500 \cos30 +500 \sin30 + R_5 \\ ∴Σ F_x (→ +ve)=0 \\ ∴R_5+500 \sin30=0 \\ ∴R_5= -500 \sin30 \\ ∴R_5= -250N \\ ∴R_5=250N (→) \\ ∴R_3=500 \cos30+500 \sin30-500 \sin30=500 \cos30 \\ ∴R_3=433.013 N \\ Σ F_x=0 \\ ∴R_1-500 \sin30-R_5= 0\\ ∴R_1-250-250= 0 \\ ∴R_1= 500N \\ Σ F_y=0 \\ ∴R_2-500 \cos30= 0 \\ ∴R_2= 500 \cos30= 433.013N $

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