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A cylinder B, WB=1000N, dia. 40cm, hangs by a cable AB=40 cm rests against a smooth wall. Find out reaction at C and TAB.
written 8.7 years ago by gravatar for teamques10 teamques10 ★ 69k •   modified 4.9 years ago

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engineering mechanics
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written 8.7 years ago by gravatar for teamques10 teamques10 ★ 69k •   modified 8.7 years ago

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∝=sin−1(2040)=30°

F.B.D

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By Applying Lami’s theorem,

∴ \dfrac {T_AB}{\sin⁡(90) } = \dfrac { R_C}{\sin⁡(150) } = \dfrac W{\sin⁡(120)} \\ ∴ R_C=(\dfrac {\sin150}{\sin 120})1000=577.35N \\ ∴ T_AB=(\sin90/(\sin 120))W=1000(1/(\sin 120))=1154.70N

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