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A cylinder B, WB=1000N, dia. 40cm, hangs by a cable AB=40 cm rests against a smooth wall. Find out reaction at C and TAB.

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∝=sin1(2040)=30°

F.B.D

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By Applying Lami’s theorem,

TABsin(90)=RCsin(150)=Wsin(120)RC=(sin150sin120)1000=577.35NTAB=(sin90/(sin120))W=1000(1/(sin120))=1154.70N

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