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A cylinder B, WB=1000N, dia. 40cm, hangs by a cable AB=40 cm rests against a smooth wall. Find out reaction at C and TAB.
1 Answer
written 8.7 years ago by | • modified 8.7 years ago |
∝=sin−1(2040)=30°
F.B.D
By Applying Lami’s theorem,
∴TABsin(90)=RCsin(150)=Wsin(120)∴RC=(sin150sin120)1000=577.35N∴TAB=(sin90/(sin120))W=1000(1/(sin120))=1154.70N