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Find support reactions at A & B for the beam shown.

enter image description here

1 Answer
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As Shown in FBD,

Taking two components of RA & taking support reaction at pt. B which inclined at angle 60 with horizontal. Also converting the trapezoidal load into equivalent point loads we get FBD

Now , applying conditions of equilibrium

Fx=HARBcos60=0(1)FY=VA12018080+RBsin60=0(2)MFA0[     +ve]120(5)+180(6)RBsin60(10)+80(13)=0RB=314.08 KN  at  θ=60

Putting in eqs. (1) and (2), we get

HA=157.04KN,VA=108KNSo ,RA=190.59KN  atθ=34.52

Support reaction at A is 190.59KN at θ=34.52 & at B is RB=314.08KN at θ=60

enter image description here

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