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Find support reactions at A & B for the beam shown.
1 Answer
written 8.7 years ago by |
As Shown in FBD,
Taking two components of RA & taking support reaction at pt. B which inclined at angle 60∘ with horizontal. Also converting the trapezoidal load into equivalent point loads we get FBD
Now , applying conditions of equilibrium
∑Fx=HA−RBcos60=0−−−−−(1)∑FY=VA−120−180−80+RBsin60=0−−−−(2)∑MFA≅0[ +ve]120(5)+180(6)−RBsin60(10)+80(13)=0RB=314.08 KN at θ=60∘
Putting in eqs. (1) and (2), we get
HA=157.04KN,VA=108KNSo ,RA=190.59KN atθ=34.52∘
Support reaction at A is 190.59KN at θ=34.52∘ & at B is RB=314.08KN at θ=60∘