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Calculate the number of atoms per unit cell of a metal

having the lattice 5 parameter 2.9A0 and density 7.87 gm/cm2. Atomic weight of metal is 55.85. Avogadro number is 6.023×1023/gmmole. - Mumbai university > FE > SEM 1 > Applied Physics 1

Marks: 5M

Year: May 2015

1 Answer
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Given:

a=2.9A=2.9×1010m

Density(ρ)=7.87gm/cm2=7.87×101m

M=55.85

Na=6.023×1023gm/mole=6.023×1026kg/Nm

To find: n = ?

soln: ρ=MnNAa3

n=ρ×NA×a3M

n=7.87×101×6.023×1026×(2.9×1010)355.85

n=20.699×105

n=0.207×103

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