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Find the interplaner spacing between the family of planes (1 1 1) in a crystal of lattice constant 3A^o.

Mumbai university > FE > SEM 1 > Applied Physics 1

Marks: 3M

Year: Dec 2013

1 Answer
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Given:-

(h l k) = (1 1 1)

a = 3$A^0$

To Find:-

Inter-planar distance (d)

Solution:-

We know that,

$d = \frac{a}{\sqrt{h^2 + k^2 + I^2}}$

$d = \frac{3}{\sqrt{1^2 + 1^2 + 1}} = \sqrt{3}$

$d = 1.732 A^0$

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