Given:

$V= 141.4 \sin 314 t \\ \text{On complaining with,} \\ V= Vm \sin 2 πft \\ We get, 2πf= 314 \\ ∴ f= 314/2π = 50 Hz \\ Vm \text{(Peak value)} = 141.4 V \\ ∴ Vrms = Vm/\vee2 = 141.4V/\vee2 = 100V \\ Vavg = 0.63 Vm = 0.63 * 1414V= 89 V \\ \text{At t= rms} \\ V(t)= 141.4 \sin (314 *3*10-3) \\ = 141.4 \sin (0.942 rod) \\ =141.4 \sin (0.942 *180) \\ =141.4 \sin (53.97) π \\ =V(t) =114.36 V$