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For the given circuit find the value of 'RL' so the maximum power dissipated in it. Also find Pmax.
written 8.4 years ago by gravatar for teamques10 teamques10 ★ 68k modified 2.8 years ago by gravatar for pedsangini276 pedsangini276 • 4.8k

Mumbai University > FE > Sem 1 > Basic Electrical and Electronics Engineering

Marks: 8 M

Year: DEC 2013, DEC 2012
basic electrical engineering
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written 8.4 years ago by gravatar for teamques10 teamques10 ★ 68k

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Step I:

Calculation of VTH

I1 = 100/40 + 60 = 1A

I2= 100/50+50 = 1A

Writing the VTH equation,

-40 I1 + VTH – 2 + 50 I2= 0

-40 (1) + VTH-2 + 50(1) = 0

VTH = -8V

=8V (terminal B is positive w.r.t A)

RTH= 49Ω

Step III: Value of R

For maximum power transfer R= RTH= 49o Ω

Step IV:

Pmax = V2TH/4RH = 82/4* 49 = 0.33 W
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