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Determine the value of resistance R using KVL & KUL

written 8.4 years ago by teamques10 ★ 68k

modified 2.8 years ago by sagarkolekar ★ 11k

basic electrical engineering

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written 8.4 years ago by teamques10 ★ 68k

I2 = 5/ 1.2 * 10-3 = 3.17mA

I1 = 5/600 = 8.33 mA

∴ I1 + I2

= 4.17 + 8.33 = 1.2 mA

Applying KUL to the circuit,

35 = 600 I1 – RI = 0

35 = 600 (8.33 * 10-3) – R (12.5 * 10-3) = 0

R = 2.4 kΩ

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