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Four concurrent forces act at a point as shown. Find their resultant.
written 8.4 years ago by gravatar for teamques10 teamques10 ★ 68k •   modified 4.5 years ago

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engineering mechanics
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written 8.4 years ago by gravatar for teamques10 teamques10 ★ 68k

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Let the inclination of $40 N$ force be $θ. $

$Θ = \tan^{-1} (3/4) = 36.87 $

Resolving the forces along X-axis,

$∑Fx = Rx = 15 + 40 \cos θ- 25 \cos 40 = 27.8489→ ------- (I) $

Resolving forces along Y axis.

$∑Fy = Ry= 50 + 40\sin θ +25\sin 40 = 90.0697↑ -------- (2) $

From (I) & (2) Resultant force

$R^2 = Rx^2+Ry^2 \\ R = 94.3 N↗ \\ .α =\tan^{-1}(Ry/Rx) = 72.8° $
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