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Steam at 500 kPa having a quality of 0.9 expands adiabatically and reversibly to a final pressure of 100 kPa. Determine its final condition
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Given:

P1=500kPa,x1=0.9,P2=500kPa,s1=s2

Now since process is isentropic,

s1=s2

From Steam tables, 1.303+x2(6.057)=1.806+0.9(4.959)

x2=0.8198

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