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Steam at 500 kPa having a quality of 0.9 expands adiabatically and reversibly to a final pressure of 100 kPa. Determine its final condition

written 8.4 years ago by teamques10 ★ 68k

•   modified 5.2 years ago

thermodynamics

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written 8.4 years ago by teamques10 ★ 68k

Given:

$P_1 = 500 kPa, x_1= 0.9, P_2 = 500 kPa, s_1= s_2$

Now since process is isentropic,

$s_1= s_2$

From Steam tables, $1.303 + x_2(6.057) = 1.806 +0.9(4.959)$

$x_2= 0.8198$

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