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How much of the 1200 KJ of thermal energy at 700 K can be converted to useful

written 8.8 years ago by teamques10 ★ 69k

•   modified 8.8 years ago

work if the environment is at 25°C -

Mumbai university > MECH > SEM 3 > THERMO

Marks: 4M

Year: May 2014

thermodynamics

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written 8.8 years ago by teamques10 ★ 69k

Given : Q = 1200 KJ , T = 700K , T0 = 298K

The available energy is given as,

$A = Q(1 - \frac{T_0}{T})$

$A = 1200 (1 - \frac{298}{700})$

$A = 689.142 KJ$

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