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With the help of Buckingham π-theorem show that for a forced convection
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written 8.8 years ago by
teamques10
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Step 1: Determination of dimension of all variables
| Variables | Units | Dimensiond |
|---|---|---|
| ρ | kg/m3 | ML-3 |
| v | m/s | LT-1 |
| μ | N.sm2=kg.ms2×sm2=kgm.s | ML-1T-1 |
| l | m | L |
| h | Wm2K=Nms×1m2K,=kg.ms2×ms×1m2K=kgs3K | MT-3θ-1 |
| K | WmK=Nms×1mK,=kg.ms2×ms×1mK=kg.ms3K | MLT-3θ-1 |
| Cp | JkgK=Nmkg.K×kg.ms2×mkg.K | L2T-2θ-1 |
Step 2: Number of variables (m) = 7
Step 3: Number of basic dimension (n) = 4 …
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