Given,
d = 2cm = 0.02m (Diameter of pipe)
t1 = 40℃ = 313K (Temperature of pipe)
t2 = 50℃ = 323K (Surrounding temperature)
h = 20W/m2K (Convective heat transfer coefficient of surrounding medium)
l = 1m (Length of pipe)
Find: (1) Q (Heat transfer rate)
Solution:
Heat transfer rate
Q = dtR = t1 - t21h. As = 313 - 323120 × π × 0.02 × 1
Q = -12.566 W (-ve sign indicates that heat flows from surrounding medium to pipe)
Case 2
Given,
d = 2cm = 0.02m (Diameter of pipe)
t1 = 40℃ = 313K (Temperature of pipe)
t2 = 30℃ = 303K (Surrounding temperature)
h = 70W/m2K (Convective heat transfer coefficient of surrounding medium)
l = 1m (Length of pipe)
Find: (1) Q (Heat transfer rate)
Solution:
Heat transfer rate
Q = dtR = t1 - t21h. As = 313 - 303170 × π × 0.02 × 1
Q = 43.982 W (+ve sign indicates that heat flows from pipe to surrounding medium)