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Design a short axially loaded square column to carry an axial load of 2250kN. Use M20 concrete and Fe415 steel. Adopt reinforcement details.
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written 8.8 years ago by |
P=2250kN M20 & Fe415
$P_u=1.5×2250=3375 kN \\ \text { Assume 1% steel of gross c/s }\\ \text {99% concrete of gross c/s }\\ Asc =0.01 A_g\\ Ac = 0.99 A_g \\ Now \space P_{uc}=0.4 f_{ck} A_c+0.67 f_y A_{sc} \\ 3375 ×10^3=[0.4 ×20×0.99 A_g+0.67 ×415×0.01 A_g] \\ A_g=315405.82 mm^2 \\ …