written 8.8 years ago by | • modified 4.3 years ago |
Use Fe415 steel and M20 grade concrete. Use following BM coefficient. Negative moment at continuous
written 8.8 years ago by | • modified 4.3 years ago |
Use Fe415 steel and M20 grade concrete. Use following BM coefficient. Negative moment at continuous
written 6.4 years ago by | • modified 6.4 years ago |
Short span | Long span |
---|---|
0.0625 | 0.047 |
Positive moment at midspan
Short span | Long span |
---|---|
0.037 | 0.037 |
Assume beam width (b) = 230mm
lylx=5+0.234+0.23=5.234.23=1.23<2
Therefore, it is a two way slab
d=short effective span(S/D ratio×M.F)
dr=423026×1.4=116.2=125
D=dr+d′=125+25=150mm
Load Calculation
D.L=D×25=0.15×25=3.75kN/m2
L.L=1kN/m2
F.F=1kN/m2
Total=8.25kN/m2
Factoredload(wd)=8.25×1.5=12.375=12.375kN/m
+ve BM(Mux=axwdlx2=0.037×12.7×4.232
(Mux)+ve=8.19lNm
(Mux)−ve=axwd(lx)2=0.0625×12.37×4.232
(Mux)−ve=13.83kNm
(Muy)−ve=aywd(lx)2=0.047×13.37×4.232
(Muy)−ve=10.41kNm
(Mumax=0.138fckbd2=0.138×20×1000×1252
=43.125kNm>[(Mux)+ve(Muy+ve(Mux−ve(Muy−ve
Therefore Safe.
(Astx)+ve=0.5×20×1000×125415×[1−√1−4.6×8.19×10620×1000×1252]
=187.39mm2≈188mm2
(Astx)−ve=0.5×20×1000×125415×[1−√1−4.6×13.83×10620×1000×1252]
=324mm2
Assume 8mm ϕ bars ϕx=ϕy=8dy=d−dx2−dy2
=125−82−82=117mm
(Asty)+ve=0.5×20×1000×117415×[1−√1−4.6×8.19×10620×1000×1172
=201mm2
(Asty)−ve=0.5×20×1000×117415×[1−√1−4.6×10.41×10620×1000×1172
=258mm2
Astmin=0.12bd100=0.12×1000×150100
180mm2<[(Astx)=ve,(Astx)−ve,(Asty)+ve,(Asty)−ve]
Therefore Safe.
Spacing -ve = 1000×π/4×82324=155.14≈150mm
Spacing -ve = 1000×π/4×82258=194.82≈175mm