Perform histogram stretching so that the new image has a dynamic range of [0,7]

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written 8.8 years ago by

teamques10 ★ 69k

• modified 4.8 years ago

image processing

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written 8.8 years ago by

teamques10 ★ 69k

$Here, r_{min} = 0 \\ r_{max} = 3 \\ s_{min} = 0 \hspace{1cm} s_{max} = 7 \\ s = s_{max} - s_{min}/r_{max} – r_{min}(r –r_{min}) + s_{min} \\ Therefore,s = 7/3 (r-0)+0 \\ When,r=0 ,s=0 \\ r=1 ,s = 7/3 (1-0)=2.3 ≈ 2 \\ r=2 ,s = 7/3 (2-0) = 4.67 ≈ 5 \\ r=3 ,s = 7/3 (3-0) = 7$ \

Therefore,we have

r=0	S=0
r=1	S=2
r=2	S=5
r=3	S=7

INPUT HISTOGRAM

OUTPUT HISTOGRAM:

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