1 kg of Nitrogen gas at 1 bar and 300 K is compressed to 5bar and 400k. Find

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written 8.8 years ago by

teamques10 ★ 69k

• modified 5.6 years ago

i) index of process ii) work transfer iii) Heat transfer iv) Change in internal Energy

thermodynamics

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written 8.8 years ago by

teamques10 ★ 69k

Given :

m = 1kg

M = 28 ( molecular weight of nitrogen )

P1 = 1 bar; T1 = 300K

P2 = 5bar; T2 = 400K

i) Finding index

P1/P2 = (T1/T2)^(n/n-1)

1/5 = (300/400)^ (n/n-1)

On solving in calci we get, n = 1.218

W = …

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