Find the acid value of vegetable oil whose 5 ml requires 2ml of N/100 KOH during lubrication(density of oil =0.92g/ml)

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written 8.5 years ago by

teamques10 ★ 69k

• modified 8.5 years ago

Mumbai University > First Year Engineering > Sem1 > Applied Chemistry 1

engineering chemistry

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written 8.5 years ago by

teamques10 ★ 69k

Weight of oil=volume in ml * density = 5*0.92 = 4.6 gms

Normality of KOH= N/100 = 0.01 N

Volume of KOH = 2ml

ACID VALUE = $\frac{vol.\ \ of \\ KOH \ \ required X Normality \ \ of \ \ KOH X 56}{weight \ \ of \ \ oil \ \ in \ \ gms}$

$= \frac{2 \times 0.01 \times 56}{4.6}$

= 0.2434 mgs KOH

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