0
450views
A rectangular wave guide of cross section 5 cmX2 cm is used to propagate TM11 mode at 9GHz. Determine the cutoff wavelength and wave impedance.
1 Answer
0
25views

Solution:

λc=2abm2b2+n2a2

Here, a=2×102 m;b=5×102 m

Thus, Cutoff Wave length λc=9.285 cm and fc=cλc=3.23GHz. Wave impedance for TM mode $=\eta \sqrt{1-\left(\frac{f c}{f}\right)^2} \$

=3771(3.239)2 =351.8 ohms

Please log in to add an answer.