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A rectangular wave guide of cross section 5 cmX2 cm is used to propagate TM11 mode at 9GHz. Determine the cutoff wavelength and wave impedance.
1 Answer
written 2.3 years ago by |
Solution:
λc=2ab√m2b2+n2a2
Here, a=2×10−2 m;b=5×10−2 m
Thus, Cutoff Wave length λc=9.285 cm and fc=cλc=3.23GHz. Wave impedance for TM mode $=\eta \sqrt{1-\left(\frac{f c}{f}\right)^2} \$
=377√1−(3.239)2 =351.8 ohms