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Find the cut off frequency for TM11 mode, given dimensions of the waveguide 2 cm and 4 cm respectively.
1 Answer
written 2.3 years ago by | • modified 2.3 years ago |
Solution:
λc=2ab√m2b2+n2a2
Here,
a=2×10−2 m;b=4×10−2 m
Thus,
λc=3.5777 cm and fc=cλc=8.386GHz
λc=2ab√m2b2+n2a2
Here,
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