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Find the cut off frequency for TM11 mode, given dimensions of the waveguide 2 cm and 4 cm respectively.
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Solution:

λc=2abm2b2+n2a2

Here,

a=2×102 m;b=4×102 m

Thus,

λc=3.5777 cm and fc=cλc=8.386GHz

λc=2abm2b2+n2a2

Here,

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