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A reflex klystron operates under following conditions: V0=625 V, L=1 mm,Rsh =14 KΩ and f=8GHz. ..

A reflex klystron operates under following conditions: V0=625 V, L=1 mm,Rsh =14 KΩ and f=8GHz. If the device is operating at the peak of 134 mode, Calculate a) Repeller Voltage and b) Efficiency.

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Solution:

Reflex klystron,

Given:

V0=625 V,L=1 mmRsh=14kΩf=8CH2

the device operating mode is 13/4 Hence n=2

calculation,

 a) Reseller voltage (vγ)v0(vr+v0)2=em(2nππ/2)28ω2L2

625(V0+625)2=1.759×1011×(2×2×ππ/2)28×(2π×8×109)2(1×103)2

on simplification, we set

[vγ=145.701 volt ]

b) Efficiency:

The efficiency is expressed as -

η=2xJ1(x)2nππ/2=2xi

where x=2.408

J1(x)=0.52

=2×2.408×0.522×2×ππ/2×100=22.7%

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