Suppose the data sample S contains n = 40 examples and that hypothesis h commits r = 12 errors over this data.

The sample error is errors(h) = r/n = 12/40 = 0.30

With the 68% confidence interval estimate for errorD (h).

Solution:

$\operatorname{error}_S(h) \pm 1.00 \sqrt{\frac{\operatorname{error}_S(h)\left(1-\operatorname{error}_S(h)\right)}{n}}$

$\begin{aligned} & =0.30 \pm(1.00 * 0.07) \\\\ & =0.30 \pm 0.07 \\ \end{aligned}\\ $