0
2.2kviews
A glass fibre exhibits material dispersion given by |λ2d2ndλ2| of 0.025. Determine the material dispersion parameter at a wavelength of 0.85μm,

A glass fibre exhibits material dispersion given by |λ2d2ndλ2| of 0.025. Determine the material dispersion parameter at a wavelength of 0.85μm, and estimate the pulse broadening per kilometer with a spectral width of 20 nm at this wavelength.

1 Answer
2
513views

Solution:

We know that the pulse broadening is given by,

Δτ=Dmat (λ)LΔλ

where Dmat (λ) defines material dispersion and is given by

Dmat(λ)=λc[d2ndλ2]=1λc[λ2d2ndλ2]

Given,

λ=0.85μm,[λ2d2ndλ2]=0.025 and $c=3 \times …

Create a free account to keep reading this post.

and 3 others joined a min ago.

Please log in to add an answer.