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Determine the normalized frequency at 0.82μm for a step-index fiber having a 25μm core radius, n1=1.48 and n2=1.46. How many modes propagate in this fiber at..

Determine the normalized frequency at 0.82μm for a step-index fiber having a 25μm core radius, n1=1.48 and n2=1.46. How many modes propagate in this fiber at 0.82μm?

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Solution:

Solution: We know that the normalized frequency V is given by,

V=2πaλ(n21n22)

Given

α=25μm,λ=0.82μm,n1=1.48 and n2=1.46.

V=2π×250.82(1.48)2(1.46)2=46.45

Since the number of modes propagates through the fiber is,

V22,

$N=\frac{V^2}{2} …

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