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Design as optical fiber link for transmitting 15Mb/sec of data for a distance of 4 km with BER of 10−9.
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written 2.3 years ago by |
Solution:
Bandwidth x Length =15Mb/sec×4 km=(60Mb/sec)km
Selecting optical source: LED at 820 nm is suitable for short distances. The LED generates 10dBm optical powers.
Selection of optical fiber: Step-index multimode fiber is selected. The fiber has bandwidth length product of 100(Mb/s)km.
Splicing loss Is=0.5 dB/ slice
Connector loss Ic=1.5 dB
System link power margin Pm−8 dB
Fiber attenuation αf=6 dB/km
Actual total loss =(2×lc)+αfL+Pm
PT=(2×1.5)+(6×4)+8
PT=35 dB
Maximum allowable system loss:
Pmax= Optical source output power- optical receiver sensitivity Pmax=−10dBm−(−50dBm)Pmax=40dBm