written 23 months ago by |
Solution:
Bandwidth x Length $=15 \mathrm{Mb} / \mathrm{sec} \times 4 \mathrm{~km}=(60 \mathrm{Mb} / \mathrm{sec}) \mathrm{km}$
Selecting optical source: LED at $820 \mathrm{~nm}$ is suitable for short distances. The LED generates $10 \mathrm{dBm}$ optical powers.
Selection of optical fiber: Step-index multimode fiber is selected. The fiber has bandwidth length product of $100(\mathrm{Mb} / \mathrm{s}) \mathrm{km}$.
Splicing loss $\mathrm{I}_{\mathrm{s}}=0.5 \mathrm{~dB} /$ slice
Connector loss $\mathrm{I}_{\mathrm{c}}=1.5 \mathrm{~dB}$
System link power margin $\mathrm{Pm}-8 \mathrm{~dB}$
Fiber attenuation $\alpha \mathrm{f}=6 \mathrm{~dB} / \mathrm{km}$
Actual total loss $=(2 \times \mathrm{lc})+\alpha \mathrm{fL}+\mathrm{Pm}$
$P T=(2 \times 1.5)+(6 \times 4)+8$
$\mathrm{PT}=35 \mathrm{~dB}$
Maximum allowable system loss:
$ \begin{aligned} & P_{\max }=\text { Optical source output power- optical receiver sensitivity } P_{\max }=-10 \mathrm{dBm}-(-50 \mathrm{dBm}) \\\\ & P_{\max }=40 \mathrm{dBm}\\ \end{aligned}\\ $