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A transmitter has an output power of 0.1 mW. It is used with a fiber having NA= 0.25, attenuation of 6 dB/km, and length of 0.5 km. ..

A transmitter has an output power of 0.1 mW. It is used with a fiber having NA= 0.25, attenuation of 6 dB/km, and length of 0.5 km. The link contains two connectors with a 2 dB average loss. The receiver has a minimum acceptable power (sensitivity) of – 35 dBm. The designer has allowed a 4 dB margin. Calculate the link power budget.

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Solution:

Source power Ps

=0.1 mW

Ps=10dBm

Since NA=0.25

Coupling loss

=10log(NA2)

=10log(0.252)

=12 dB

Fiber loss =αf×L

If=(6 dB/km)(0.5 km)If=3 dB

Connector loss =2(2 dB)

$ I_c=4 \mathrm{~dB} …

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