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Given a sequence x(n) for 0n3, where x(0)=1,x(1)=3,x(2)=3, and x(3)=4. Evaluate its DFT X(k).
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Solution:

Since N=4,W4=ejπ/2, then using:

X(k)=3n=0x(n)Wkn4=3n=0x(n)ejπkn2

Thus, for k=0

$ \begin{aligned} & X(0)=\sum_{n=0}^3 x(n) e^{-j 0}=x(0) e^{-j 0}+x(1) e^{-j 0}+x(2) e^{-j 0}+x(3) e^{-j 0} \\\\ &=x(0)+x(1)+x(2)+x(3) \\\\ &=1+2+3+4=10 \\\\ & \text { for } k=1 \\\\ …

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