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Find the Initial and final Halves, x(z)=1+z110.25z2
1 Answer
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Solution:

Initial Value,

x(0)=ltzx(z)=ltz1+z110.25z2

=1+110.2502=1+010=1

x(0)=1

Final Value,

x()=ltz1(1z1)×(z)=ltz1(1z1)(1+z1)10.25z2

=ltz11z210.25z2

=ltz1z21z225

=111.25=0

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