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Find the direct form II structure of, H(S)=5S3−4S2+11S−2(S−14)(S2−S+12)
1 Answer
written 2.3 years ago by |
Solution:
H(S)=5S3−4S2+11S−2(S−14)(S2−S+12)
=5S3−4S2+11S−2S3−S24−S2+S4+S2−18
H(S)=5S3−4S2+11S−2S3−5S24+3S4−18
=5−4S+11S2−2S31−54S+34S2−18S3