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Determine the frequency response and impulse response, y(n)−16y(n−1)−16y(n−2)=x(n)
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written 2.3 years ago by |
Solution:
y(n)−16y(n−1)−16y(n−2)=x(n)
Applying DTFT,
Y(ejω)−16e−jωY(ejω)−16e−2jωY(ejω)=X(ejω)
Frequency response,
H(ejω)=Y(ejω)X(ejω)=11−16e−jω−16e−2jω
=e2jωe2jω−16ejω−16
$ \begin{gathered}\\ \frac{H\left(e^{j \omega}\right)}{e^{j \omega}}=\frac{e^{j \omega}}{e^{2 …