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Determine the frequency response and impulse response, y(n)16y(n1)16y(n2)=x(n)
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Solution:

y(n)16y(n1)16y(n2)=x(n) 

Applying DTFT,

Y(ejω)16ejωY(ejω)16e2jωY(ejω)=X(ejω) 

Frequency response,

H(ejω)=Y(ejω)X(ejω)=1116ejω16e2jω

=e2jωe2jω16ejω16

$ \begin{gathered}\\ \frac{H\left(e^{j \omega}\right)}{e^{j \omega}}=\frac{e^{j \omega}}{e^{2 …

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