0
286views
Find inverse Fourier transform X(jΩ)=δ(Ω)
1 Answer
0
3views

Solution:

F1[X(jΩ)]=F1[δ(Ω)]

x(t)=12πX(jΩ)ejΩtdΩ

=12πδ(Ω)ejΩtdΩ=12π[1]

F1[δ(Ω)]=12π

Create a free account to keep reading this post.

and 2 others joined a min ago.

Please log in to add an answer.