A digital filter with a $3 \mathrm{~dB}$ bandwidth of $0.4$ is to be designed from the analog filter whose system response is:

$H(s)=\frac{\Omega_c}{s+2 \Omega_c}$

Use the bilinear transformation and obtain $H(z)$.

Solution:

We know that,

$\Omega_c=\frac{2}{T} \tan \frac{\omega_c}{2}\\ $

$\Omega_c=\frac{2}{T} \tan \frac{0.4 \pi}{2}=\frac{1.453}{T}\\ $

This system response of the digital filter is given by,

$H(z)=H_a(s) \mid=\frac{2}{T}\left(\frac{1-z^{-1}}{1+z^{-1}}\right)\\ $

$=\frac{\Omega_c}{\frac{2}{T}\left(\frac{1-z^{-1}}{1+z^{-1}}\right)+2 \Omega_c}=\frac{\frac{1.453}{T}}{\frac{2}{T}\left(\frac{1-z^{-1}}{1+z^{-1}}\right)+2\left(\frac{1.453}{T}\right)}\\ $

$\begin{aligned}\\ & =\frac{1.453\left(1+z^{-1}\right)}{2\left(1-z^{-1}\right)+2\left(1+z^{-1}\right) 1.453} \\\\ & =\frac{1+z^{-1}}{3.376-0.624 z^{-1}}\\ \end{aligned}\\ $