0
700views
Solve x2sinx3=0 correct to two significant figures by Newton Raphson method correct up to 5 significant digits.
1 Answer
0
121views

Solution:

Let f(x)=x2sinx3

f(0)=3,f(1)=22sin1,f(2)=12sin2,f(3)=2sin3,f(4)=12sin4f(2)=5+2sin2,f(1)=4+2sin1

As f(3)f(4)<0 by Intermediate value Theorem the root of the real root of the equation f(x)=0 lies between 3 and 4

Let x0=4 be the initial guess to the equation (2).

Then x1=x0[f(x0)/f(x0)]=2f(2)/f(2)=3.09900

x2=x1[f(x1)/f(x1)]=1.099f(1.099)/f(1.099)=3.10448x3=x2[f(x2)/f(x2)]=3.10450x4=x3[f(x3)/f(x3)]=3.10451

Please log in to add an answer.