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Convert the analog filter with the system function, Ha(s)=s+0.1(s+0.1)2+9
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written 2.3 years ago by |
Solution:
Ha(s)=1/2s+0.1−j3+1/2s+0.1+j3
Then the transfer function of the digital filter
H(z)=1/21−e−0.1Tej3Tz−1+1/21−e−0.1Tej3Tz−1H(z)=1−(e−0.1Tcos3T)z−11−(2e−0.1Tcos3T)z−1+e−0.2Tz−2