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What is the total hardness of sample of water containing following impurities in $mg/lCa(HCO3)2=162$ , CaCl2=22.2 , NaCl=20 , $MgCl_2=95$

written 8.8 years ago by teamques10 ★ 69k

•   modified 8.8 years ago

Mumbai University > First Year Engineering > Sem1 > Applied Chemistry 1

Marks: 3M

Year: May 13, Dec13, Dec 122

engineering chemistry

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written 8.8 years ago by teamques10 ★ 69k

Impurities	Quantity Mg/lit	Multiplying factor	CaCO3 equivalents in ppm
Ca(HCO3)2	162	162*100/162	100
CaCl2	22.2	22.2*100/111	20
NaCl	20	0	Not counted
MgCl2	95	95*100/95	100

Temporary hardness= Ca(HCO3)2=100ppm

Permanent hardness= CaCl2 + MgCl2 = 120 ppm

∴ Total hardness= 100+120= 220 ppm

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