written 2.0 years ago by | • modified 2.0 years ago |
Illustrate the working of V-to-I and I-to-V converters with neat circuit diagrams.
written 2.0 years ago by | • modified 2.0 years ago |
Illustrate the working of V-to-I and I-to-V converters with neat circuit diagrams.
written 2.0 years ago by |
$$\frac{V_{out} - V}{R_f} = I_p + I^-$$
As The O/P is connected to inverting V through feedback resistor $R_p$. Negative feedback configuration of op amp is given as $V^{-} = V^+ = 0$. Assuming $I^- = 0$ and the output voltage is obtained by follow equation -
$$V_{out} = I_p R_p$$
For the input loop, the voltage equation is -
$$V_{in} = V_D + V_F$$
$$Since\ F\ is\ very\ large,$$
$$V_D = 0$$
$$So,\ V_{in} = V_F$$
$$Since,\ the\ input\ to\ the\ op-amp.$$
$$I_B = 0$$
$$V_{in} = I_L * R$$
$$Therefore,\ I_I = I_L = \frac{V_{in}}{R}$$
To determine the load current e should known the I/P voltage and I/P resistance between $I_L \lt V_{in}.$
The load current is directly proportional to input voltage and controlled by resistor R.