The specification for a certain residential fire-suppression system is that water should be sprayed at the rate q of 10 gal/min. For the revision of the technical manual intended for customers outside the United States, express the flow rate in the SI based on a time interval of 1 s.

Solution:

Approach:-

we could express volume in the SI Using the dimensions of eigther $\mathrm{m}^3$ or $L$. So, we initially decide to Convert volume to liters with the Conversion factor 1 gal $=3.785 \mathrm{~L}$. **Solution:-** Converting dimensions for both volume and time. $ \begin{aligned}\ q &=\left(10 \frac{\mathrm{gal}_{\mathrm{m}}}{\mathrm{min}}\right)\left(\frac{1}{60} \frac{\mathrm{min}}\{\mathrm{s}}\right)\left(3.785 \frac{\mathrm{L}}{gal}\right) \\ &=0.6308\left(\frac{\mathrm{gaL}}{\mathrm{min}}\right)\left(\frac{\mathrm{min}}{\mathrm{s}}\right)\left(\frac{1}{gal}\right) \\ &=0.6308 \mathrm{Ls}^{-1}\ \end{aligned}\ $ **Discussion:-** However, since a cubic meter is 1000 times larger then a liter, The dimension $L / 9$ turns out to be better suited for the problem at, $ q=0.6308 \frac{L}{S}\ $