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Realise the following function in Foster 1 and Foster- 2 form. z(s)=3(s+2)(s+4)(s)(s+3)
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Solution:

Foster −1 from:

z(s)=3(s+2)(s+4)(s)(s+3)....(1)=3s2+18s+24s2+3sz(s)=3+9S+24s2+3S=Z1(s)+Z2(s)...(2)

Where

z1(s)=3

And

z2(s)=9s+24(s)(s+3)=As+Bs+3}....(3)

A=9S+24(s)(S+3)|S=0=0+240+3=8B=9S+24S|S=3=27+243=1

from (3)

z2(s)=8s+1s+3=Z2(s)+z2(s)...(4)

Where

Z2(s)=8s=118s

And

z2(s)=1s+3=1y2(s)y2(s)=s+3

Foster 1 form is

enter image description here

Foster −2 from:

V(s)=1z(s)=(s)(s+3)3(s+2)(s+4)....(1)=s2+3s3s2+18s+24

polarity of remainder is -ve, divide both side of equation by S.

y(s)S=S+33(S+2)(S+4)=AS+2+BS+4}...(2)

A=s+33(s+4)|s=2=2+33(2+4)=16

B=s+33(s+2)|S=4=4+33(4+2)=16

from eq1

y(s)s=1/6s+2+1/6s+4

y(s)s=16s+12+16S+24

Y(S)=S6S+12+S6S+24

y(s)=y1(s)+y2(s)...(3)

Where y1(s)=s6s+12=1[6s+12s]

=16+125=1Z1(s)

Z1(s)=6+129=6+1112s

And

y2(s)=s6S+24=1[6s+24s]=1[6+24s]=1Z2(S)Z2(S)=6+24s=6+1124s

enter image description here

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