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Realise the following function in Foster 1 and Foster- 2 form. z(s)=3(s+2)(s+4)(s)(s+3)
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Solution:

Foster −1 from:

z(s)=3(s+2)(s+4)(s)(s+3)....(1)=3s2+18s+24s2+3sz(s)=3+9S+24s2+3S=Z1(s)+Z2(s)...(2)

Where

z1(s)=3

And

z2(s)=9s+24(s)(s+3)=As+Bs+3}....(3)

$ \begin{aligned} \\ &A=\left.\frac{9 S+24}{(s)(S+3)}\right|_{S=0}=\frac{0+24}{0+3}=8 \\\\ &B=\left.\frac{9 S+24}{S}\right|_{S=-3}=\frac{-27+24}{-3}=1 …

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