0
327views
Find the voltage across the 15Ω resistor in the given network using mesh analysis.

Find the voltage:

enter image description here

1 Answer
0
2views

Solution:

enter image description here

 Apply KVL to loop (1) 120a20(a+b)j20(b)j15(a)=0(20+j15)a(20+j20)b=1200......(1) Apply KVL to second loop j10(a)j15(b)15(a)+j20(b)+j15(a)=0(15j5)a+(j5)b=0Δ=|(20+j15)(20+j20)(15j5)(j5)|=(20+j15)(j5)(20+j20)(15j5)=325300j=442.29137.29

Δa=|1200(20+j20)0(j5)|=(120)(j5)=600j=600  - 90 a=ΔaΔ=600L90442.29137.29=1.356447.29 Amp  Hence voltage across 15Ω resistor is V15=15(a)=15(1.35647.29)V15=20.3447.29 Volts 

Please log in to add an answer.