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Find the value of load impedance ZL, so that maximum power can be transferred to it in the network of fig. Find maximum power.

Find the value of load impedance ZL,

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Solution:

 Part-1 - TO find " VTH " 

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VTH=50453I OR VTH=(2+j10)I KVL to loop 50453I2Ij10I=0(5+j10)I=5045I=5045(5+j10)=4.47218.434 Amp  from ea- (1) VTH=50453(4.47218.434)VTH=45.60860.25 volts 

 Part-1 - TO find " ZTH " 

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ZAB=ZTH=(2+j10)(3)=(2+j10)(3)(2+j10)+3=6+j305+j10ZTH=2.64+j0.72=2.73615.25Ω

According to the maximum power transfer theorem

ZL=ZTH=2.64j0.72=2.73615.25Ω

And Maximum power is given by

Pmax =|V2TH|4RTH=(45.608)24(2.64)Pmax =196.97 Walts 

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