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On doubling the concentration of reactant, the rate of reaction triples. Find the reaction order.

On doubling the concentration of reactant, the rate of reaction triples. Find the reaction order.

rA=k CnA

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Solution :

At CA1, the rate is

rA1=kCnA1

At CA2, the rate is

rA2=kCnA2

If rA2=kCnA2

CA2=2CA1

. we have

rA2=3(rA1)

rA2rA1=kCnA2kCnA1

rA2rA1=CnA2CnA1

$$\frac{3\left(\mathrm{-r_{A 1}}\right)}{\mathrm{-r_{A 1}}}=\frac{\left(2\mathrm {C_{A 1}}\right)^{\mathrm n}}{\left(\mathrm {C_{A …

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