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Design a mod 5 synchronous up counter using J-K flip flop
1 Answer
written 8.4 years ago by |
Step 1:
Determine the number of flip flop needed
Flip flop required are
$2^n ≥ N$
Mod 5 hence N=5
$\therefore 2^n \underline{\gt} N \\ \therefore 2^n \underline{\gt} 5 \\ N=3 \hspace{0.2cm} \text{i.e. 3 flip flop are required}$
Step 2:
Type of flip flop to be used: JK flip flop
Step 3:
1) Excitation table for JK flip flop
$Q_n$ | $Q_{n+1}$ | J | K |
---|---|---|---|
0 | 0 | 0 | $\times$ |
0 | 1 | 1 | $\times$ |
1 | 0 | $\times$ | 1 |
Now, we can derive excitation table for counter using above table as follows:
2) Excitation table for counter
Step 4
K-map simplification
For $J_C$
$J_c=Q_BQ_A$
For $K_C$
$K_C=1$
For $J_B$
$J_B=QA$
For $K_B$
$K_B=QA$
For $J_A$
$J_A=\overline{Q}_C$
For $K_A$
$K_A=1$
Step 5 Logic Diagram
Step 6: Timing Diagram